8-2[3-2(x+1)]=x+3

Solution for 8-2[3-2(x+1)]=x+3 equation:

Simplifying
8 + -2[3 + -2(x + 1)] = x + 3

Reorder the terms:
8 + -2[3 + -2(1 + x)] = x + 3
8 + -2[3 + (1 * -2 + x * -2)] = x + 3
8 + -2[3 + (-2 + -2x)] = x + 3

Combine like terms: 3 + -2 = 1
8 + -2[1 + -2x] = x + 3
8 + [1 * -2 + -2x * -2] = x + 3
8 + [-2 + 4x] = x + 3

Combine like terms: 8 + -2 = 6
6 + 4x = x + 3

Reorder the terms:
6 + 4x = 3 + x

Solving
6 + 4x = 3 + x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1x' to each side of the equation.
6 + 4x + -1x = 3 + x + -1x

Combine like terms: 4x + -1x = 3x
6 + 3x = 3 + x + -1x

Combine like terms: x + -1x = 0
6 + 3x = 3 + 0
6 + 3x = 3

Add '-6' to each side of the equation.
6 + -6 + 3x = 3 + -6

Combine like terms: 6 + -6 = 0
0 + 3x = 3 + -6
3x = 3 + -6

Combine like terms: 3 + -6 = -3
3x = -3

Divide each side by '3'.
x = -1

Simplifying
x = -1